Zoch Verlag | SKU:
17507951050803
Rück's raus! (Import)
$24.95 CAD
Unit price
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Unavailable
$24.95 CAD
Products title that includes 'PRE-ORDER' is subject to our Pre-order Policy
This item is available for pre-order. Orders will be fulfilled in order received. We will contact you if the item is unavailable.
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Delivery and Shipping
Delivery and Shipping
For more details, please refer to our Shipping and Order Information.
Pre-Order Policy
- Pre-order items are charged at the time the order is placed.
- Prices for pre-order items are subject to change based on final landed costs.
- If the final price is lower, the difference will be refunded to the customer in the form of store credit.
- If the final price is higher, customers will be given the option to either:
- Pay the difference, or
- Cancel the item for a full refund.
- Orders containing pre-order items will be placed on hold until all items in the order are available.
- Once all items have arrived and pricing remains unchanged, the order will be automatically shipped.
- Pre-orders are fulfilled on a first-come, first-served basis.
- If a pre-ordered item becomes unavailable (e.g., the publisher cancels the product), a full refund will be issued.
- Pre-orders may be cancelled and refunded by customers or the store.
- For transactions that are no longer eligible for direct refunds due to payment processor limitations, a store credit will be issued instead.
Description
Description
| Designer | Antonin Boccara |
| Publisher | Zoch Verlag |
| Players | 3-5 |
| Play time | 10 mins |
| Suggested Age | 8 and up |
Rück’s raus! is the card game for bearded bandits – whoever steals the secondmost jewels wins.
Each round, a random noble is turned face up. Then everyone plays a robber simultaneously. Whoever played the strongest bandit will enjoy the victim’s ”favor”. Usually, that player steals the noble’s jewels. Sometimes the player will let him foist something on one of the opponents or swipe something from one of them. Whoever played the weakest robber will get some pity jewels. At the end of the game, the player with the second-most jewels wins.
